Answer:
D
Step-by-step explanation:
I am confused but thats my guess
Answer:
The amount invested at 9% is $93000
The amount invested at 10% is $303000
Step-by-step explanation:
Let the amount invested at 9% interest rate be x
And the amount invested at 10% rate be y
Simple Interest from x in a year = 0.09x
Simple Interest from y in a year = 0.1y
But y = 24000 + 3x
And the sun of the interests, 0.09x + 0.1y = 38670
Now we have a simultaneous eqn
y = 24000 + 3x (eqn 1)
0.09x + 0.1y = 38670 (eqn)
Substitute y into eqn 2
0.09x + 0.1(24000 + 3x) = 38670
0.09x + 2400 + 0.3x = 38670
0.39x = 38670 - 2400
x = 36270/0.39 = $93000
y = 24000 + 3x = 24000 + 3 × 93000 = $303000
x < - 
add 
to both sides
- 3x > + 
- 3x > 
( divide both sides by - 3 )
note that when we divide/ multiply by a negative quantity we must reverse the inequality symbol
x < -
<span>Let x = 0.5333333333 ...
So 100x = 53.3333333333 ...
and 10x = 5.3333333333 ...
---------------------------------
90x = 53 – 5 = 48.
So x = 48/90 = 8/15 after reduction to lowest terms (by factor of 6)
0.3333... = ⅓. and that 0.5 = ½.
So 0.533333... = 0.5 + 0.0333333...0.5 + 0.3333.../10 = 1/2 + (1/3)/10 = 1/2 + 1/30 = 16/30 = 8/15</span>
