Answer:
1. -x²-15x-1
2. -33x⁷+10x⁶-14x⁵+4x⁴+11x²-5x+32
Step-by-step explanation:
-20x^2+5x+17 - (-19x^2+20x+18)
-20x² + 19x² + 5x - 20x + 17 - 18
-x² - 15x - 1
-20x^7+10x^6-5x+15 - (13x^7+14x^5-4x^4-11x^2-17)
-20x⁷ - 13x⁷ + 10x⁶ - 14x⁵ + 4x⁴ + 11x² - 5x + 15 + 17
-33x⁷ + 10x⁶ - 14x⁵ + 4x⁴ + 11x² - 5x + 32
Answer:
free point 3.3.3 points sorry but I just need
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
Step-by-step explanation:
length = Pi.radius.15degree/180degree
= Pi.2.15/180 = about 0,5 feet
