Which statement is true about the value of the expression below?
2 answers:
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Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.
has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5
has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable
Answer:
50 kg water.
Step-by-step explanation:
We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.
We know that two directly proportional quantities are in form , where y varies directly with x and k is constant of variation.
We are told that an 87-kg person contains 58 kg of water. We can represent this information in an equation as:
Let us find the constant of variation as:
The equation represents the relation between water (y) in a human body with respect to mass of the body (x).
To find the amount of water in a 75-kg person, we will substitute in our given equation and solve for y.
Therefore, there are 50 kg of water in a 75-kg person.