find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length
To find the perimeter of a triangle we add all the sides of the triangle
The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches
Perimeter of a triangle =
15 inches + 15 inches + 21 inches = 51 inches
So 51 inches is the perimeter
Well the answer would be 8 as the total sum would be 6 x (8) = 48
Answer:
Hello! Your answer is 276
Step-by-step explanation:
Let's just break up the equation:
(3.x2) + (6x45)
6 + 270
<u><em>Hence, the answer is 276</em></u>
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<u><em>Hope This Helps :)</em></u>
<u><em>Please mark brainliest</em></u>
<u>Given </u><u>:</u><u>-</u>
- The slope of the line through points (3,y) and (4,10) is 7 .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
As we know that the slope of the line is difference of ordinate divided by the difference of absicca as ,
m = y -10 / 3 - 4
7 (-1) = y -10
-7 = y -10
y = 10 -7
y = 3
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>3.</u>
Answer:
- D. A translation 1 unit to the right followed by a 270-degree counterclockwise rotation about the origin
Step-by-step explanation:
<em>See the picture for better visual</em>
Take segments ST and S'T'. If we extend them they will intersect at right angle.
It is the indication that the rotation is 90° or 270° but not 180°, when the corresponding segments come parallel.
The QRST is in the quadrant IV and Q'R'S'T' is in the quadrant III, which mean the rotation is 90° clockwise or 270° counterclockwise.
<u>This rotation rule is:</u>
We also see the points S and T have x-coordinate of 5 but their images have y-coordinates of -6. It means the translation to the right by 1 unit was the step before rotation.
<u>We now can conclude the correct choice is D:</u>
- A translation 1 unit to the right followed by a 270-degree counterclockwise rotation about the origin