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(5460.4)(3/8) = 2,047.65 to savings
5460.4 - 2,047.65 = 3,412.75 checking
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
I think #4 is 4 but I'm not completely sure
<h3>Answer:</h3>
2.4 potatoes/pound
<h3>Explanation:</h3>
The unit rate is the slope of the line. The slope of the line is ...
... (change in y-value)/(change in x-value)
... = (36 potatoes - 12 potatoes)/(15 pounds - 5 pounds)
... = (24 potatoes)/(10 pounds)
... = 2.4 potatoes/pound
_____
The relationship here is proportional, so the line goes through the point (0, 0) and the unit rate can be figured from any point:
... (12 potates)/(5 pounds) = (24 potatoes)/(10 pounds) = (36 potatoes)/(15 pounds) = 2.4 potatoes/pound
