First one is y=4x and the second one is y=2x
4/9 x 21/6 is this what you’re asking?
If so the answer is 1 5/9
Answer:
67,500 m²
Step-by-step explanation:
ASSUMING the fields look like this __________________
| | |
| | | W
|_________|_________|
L
Let L be the length of the combined field and W be the width
2L + 3W = 1800
2L = 1800 - 3W
L = 900 - 1.5W
A = LW
A = (900 - 1.5W)W
A = 900W - 1.5W²
Area will be maximized when the derivative equals zero.
dA/dW = 900 - 3W
0 = 900 - 3W
3W = 900
W = 300 m
L = 900 - 1.5(300)
L = 450 m
A = LW = 450(300) = 135,000 m²
so each sub field is 135000/2 = 67,500 m²
