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mr Goodwill [35]
3 years ago
7

Solve. −43x+16<79 please solve

Mathematics
2 answers:
polet [3.4K]3 years ago
6 0
-43x + 16 -16< 79 -16;   -43x ÷ -43 < 63 ÷ -43; x > -1.47
             

Svetllana [295]3 years ago
5 0
-43x + 16 < 79

Subtract 16 from both sides, 
-43x < 63

Divide -43 from both sides, 
x < -63/43

Hope this helps!

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A school administrator will assign each student in a group of n students to one of m classrooms. If 3 &lt; m &lt; 13 &lt; n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

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In a race in which six automobiles are entered and there are not ties, in how many ways can the first four finishers come in?
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 your answer would be 
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