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Juli2301 [7.4K]
3 years ago
11

Calculate the area of a sector of a circle that subtends an angle of 45° at the center of the circle, radius 14cm

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

Calculate the area of the full circle:

Area = PI x r^2

Area = 3.14 x 14^2  = 615.44 sq. cm

45 degrees is 1/8 of a circle, multiple the area of the circle by 1/8

615.44 x 1/8 = 76.93, round to 77 cm^2

The answer is B. 77 cm^2

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Simplify the following expression
vova2212 [387]

Answer:

A.( 3m+28)/4

Step-by-step explanation:

So basically since it is addition we just add 9 to -2 to get 7. So then the equation becomes (3m/4)+7. Then we will multiply 7 by 4 to get common denominator so it will be (3m+(7*4))/4 which is (3m+28)/4.

7 0
2 years ago
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borishaifa [10]
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5 0
2 years ago
Need help ASAP. i forgot all the steps after the Area is solved with 5. or if 25pi is the right answer.
maxonik [38]

Answer:

42.5\:\mathrm{m^2}

Step-by-step explanation:

The area of a sector with measure \theta in degrees is given by r^2\pi\cdot\frac{\theta}{360}, where r is the radius of the sector.

What we're given:

  • r of 5
  • \theta of 195^{\circ}

Solving, we get:

A_{sector}=5^2\pi\cdot \frac{195}{360}=13.5416666667\pi=42.5424005174\approx \boxed{42.5\:\mathrm{m^2}}

*Notes:

  • units should be in square meters (area)
  • the problem does not say whether to round or leave answers in term of pi, so you may need to adjust the answer depending on what your teacher specifically wants
7 0
2 years ago
Which graph shows the solution to this system of inequalities?<br> y&gt;-1/3x+1<br> y&gt;2x-3
Mademuasel [1]

Given:

The system of inequalities is:

y>-\dfrac{1}{3}x+1

y>2x-3

To find:

The graph of the given system of inequalities.

Solution:

We have,

y>-\dfrac{1}{3}x+1

y>2x-3

The related equations are:

y=-\dfrac{1}{3}x+1

y=2x-3

Table of values for the given equations is:

    x                   y=-\dfrac{1}{3}x+1             y=2x-3

   0                             1                              -3

   3                             0                              3

Plot (0,1) and (3,0) and connect them by a straight line to get the graph of y=-\dfrac{1}{3}x+1.

Similarly, plot (0,-3) and (3,3) and connect them by a straight line to get the graph of y=2x-3.

The signs of both inequalities are ">". So, the boundary line is a dotted line and the shaded region or each inequality lie above the boundary line.

Therefore, the graph of the given system of inequalities is shown below.

6 0
2 years ago
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