Answer:

Step-by-step explanation:

For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2+2x-2) this is True.
Answer:
The compound interest is Rs8275
Step-by-step explanation:
The rule of the compound interest is A = P
, where
- r is the interest rate in decimal
- n is the number of periods
The interest I = A - P
∵ The amount of investment is Rs25000 for 3 years
∴ P = 25000
∴ t = 3
∵ The rate of interest is 10% per annum, compounded annually
∴ r = 10% = 10 ÷ 100 = 0.1
∴ n = 1 ⇒ compounded annually
→ Substitute these value in the 1st rule above to find the new amount
∵ A = 25000
∴ A = 25000
∴ A = Rs33275
→ Use the 2nd rule above to find the interest
∵ I = 33275 - 25000
∴ I = 8275
∴ The compound interest is Rs8275