Y= -3x+10 y= -2x+6 what is x and y

Mathematics

1 answer:

Lena [83]3 years ago

7 0

Answer:

(4,-2)

Step-by-step explanation:

you could use substitution and all that, but i use desmos

You might be interested in

WHAT IS THE SLOPE (NEED HELP DROM A PRO) WILL MARK BRAINIEST IF ANSWER IS CORRECT!

ad-work [718]

Slope is -5/3, or d, plz give me brainliest

4 0

3 years ago

I don't understand how it gets the result <img src="https://tex.z-dn.net/?f=28b_%7B2%7D" id="TexFormula1" title="28b_{2}" alt="2

Maksim231197 [3]

Answer + Step-by-step explanation:

your question is about equation 4 :

$b_{1}=14-b_{2}$

Then

$\left( b_{1}\right)^{2} =\left( 14-b_{2}\right)^{2} \ \text{(this is a special product )}$

Then

$\left( b_{1}\right)^{2} =14^{2}-2\times 14 \times b_{2}+ (b_2)^2$

Then

$\left( b_{1}\right)^{2} =196-28 b_{2}+ (b_2)^2$

7 0

2 years ago

☺️☺️does anyone know☺️

Artemon [7]

The standard form of a circle:
$(x-h)^2+(y-k)^2=r^2$
Where:
(h; k) - the coordinates of a centerr - the radius
We have: $(x+5)^2+(y-10)^2=121$
therefore
$(-5;\ 10)$ - the center
$r^2=121\to r=\sqrt{121}\to r=11$ - the radius
Answer: 11

4 0

4 years ago

Read 2 more answers

Given tan of theta = -2 and pi/2; find cos(2theta)

Nata [24]

Given tan of theta = -2 and pi/2; find cos(2theta)
The identity of cos (2 theta)= $cos(2\theta )=\frac{1-tan^2\theta }{1+tan^2\theta }$
Given tan of theta = -2 and pi/2.
So, let's plug in tan theta= -2
$cos(2\theta)= \frac{1-(-2)^2}{1+(-2)^2}$
= $\frac{1-4}{1+4}$ (Squaring)
= $\frac{-3}{5}$ (simplifying)
So, cos ( 2 theta) = -3/5.
Now we can plug in tan theta = π/2
$cos(2\theta)= \frac{1-(π/2)^2}{1+(π/2)^2}$
= $\frac{1-pi^2/4}{1+pi^2/4}$ (Squaring)
= $\frac{4-pi^2}{4+pi^2}$ Simplifying
So, cos ( 2 theta)= -3/5 and (4-pi^2)/(4+pi^2)