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enot [183]
3 years ago
5

t%7B20%7D%20%2B%202%5Csqrt%7B175%7D%20" id="TexFormula1" title=" \frac{42}{ \sqrt{28} } + \frac{60}{45} - 2 \sqrt{20} + 2\sqrt{175} " alt=" \frac{42}{ \sqrt{28} } + \frac{60}{45} - 2 \sqrt{20} + 2\sqrt{175} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

4/3−4√5+13√7

Step-by-step explanation:

So for whatever reason we don't like it when the radical is in the denominator so we're going to do a process called rationalization and get rid of it. We do this by multiplying both the numerator and denominator by the radical

So for the first part we multiply the numerator and denominator by \sqrt{28} which gives us \frac{42\sqrt{28} }{28} we can then factor the 28 into sqrt(7,2,2) which simplifies to 42*2\sqrt{7}/28  So then we can simplify this and get 3\sqrt{7} We then can simplify the rest of these radicals and get 2\sqrt{20}=2\sqrt{2*2*5}=4\sqrt{5}  and 2\sqrt{175}= 2\sqrt{5*5*7}=2*5\sqrt{7} This means that so far we have the following:3\sqrt{7}+ \frac{60}{45}-4\sqrt{5} +10\sqrt{7} We can add the like terms and simplify the fraction and get 4/3−4√5+13√7

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Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

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At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

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The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

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This means that \mu = 0.7

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3 0
3 years ago
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