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adelina 88 [10]
3 years ago
5

2,4/3,8/9,16/27 Identify the series as arithmetic, geometric or neither.

Mathematics
2 answers:
leonid [27]3 years ago
8 0
The ratio of each term to the one before is 2/3. This is true for all pairs of adjacent terms, so the sequence is ...
  geometric.
gladu [14]3 years ago
6 0

Answer:Your Best Choice To Pick Would Be Geometric



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PLZ HURRY!!!!!!!!!!!!!<br> Simplify. <br> −4x^2(5x^4−3x^2+x−2)
Simora [160]

\bold{Answer}

\boxed{\bold{-20x^6+12x^4-4x^3+8x^2}}

\bold{Explanation}

  • \bold{Simplify: \ -4x^2\left(5x^4-3x^2+x-2\right)}

\bold{------------------}

  • \bold{Distribute \ Parenthesis}

\bold{\left(-4x^2\right)\cdot \:5x^4+\left(-4x^2\right)\left(-3x^2\right)+\left(-4x^2\right)x+\left(-4x^2\right)\left(-2\right)}

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\bold{-20x^6+12x^4-4x^3+8x^2}

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5 0
3 years ago
Which equation has the correct sign on the product?
eimsori [14]
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And D is wrong because a positive times a positive is a positive
7 0
3 years ago
Read 2 more answers
It is given that p varies inversely as q. If p = 12 and q = 45 find p, if q is 135.
alexgriva [62]

Answer:

p =4

Step-by-step explanation:

Given

Variation: Inversely

p = 12 when q = 45

Required

Determine p when q = 135

First, we need to determine the relationship between p and q

Since, it is an inverse variation.

The relationship is:

p\ \alpha\ \frac{1}{q}

Convert to an equation

p= k *\frac{1}{q}

p= \frac{k}{q}

Where k = constant of variation

Make k the subject

k = p * q

When p = 12 and q = 45

k = 12 * 45

k = 540

To solve for p when q = 135

Substitute 135 for q and 540 for k in p= \frac{k}{q}

p = \frac{540}{135}

p =4

6 0
2 years ago
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