All categories

3 years ago

Please help will give brainliest

Mathematics

1 answer:

telo118 [61]3 years ago

3 0

Answer:

100.53+80 = 180.53(rounded)

32pi+80 (not rounded)

Step-by-step explanation:

Triangle area = 1/2 b*h

Semi circle = (pi r^2)/2 - radius= diameter/2

h= 10 m

b=16 m

1/2*16*10

8*10

80 m

Semi circle

(pi8^2)/2

32pi

100.53 (rounded)

Add triangle +semicircle.

100.53+80 = 180.53(rounded)

32pi+80 (not rounded)

You might be interested in

Find the value of each expression using the given information cot∅=8, csc<0 find sin ∅

Oksana_A [137]

9514 1404 393

Answer:

sin(∅) = -√65/65

Step-by-step explanation:

The identities that relate the cotangent, the cosecant, and the sine are ...

csc² = 1 +cot²

sin = 1/csc

_____

For the given values, we find ...

csc(∅)² = 1 +cot(∅)² = 1 +8² = 65

csc(∅) = -√65 . . . . . . . . . . . . . . . . square root with attention to sign

sin(∅) = -1/√65 = (-√65)/65

6 0

3 years ago

Law of cosines HELP MES

Lorico [155]

Answer:

70.52 degrees

Step-by-step explanation:

To find the angles, we must first find the lengths of each side of the triangle. Adding up the respective radii, we can see that

XY = 5+4 = 9 CM

XZ = 6+5 = 11 CM

ZY = 4+6 = 10 CM

Now we can apply the cosine rule

$C\:=\:\sqrt{A^2+B^2-2ABcosx}$

We need to rearrange the rule to solve for x, our missing angle

$x\:=\:cos^{-1}\left(\frac{a^2+b^2-c^2}{2ab}\right)$

solving for our unknown angle:

$x\:=\:cos^{-1}\left(\frac{9^2+10^2-11^2}{2\cdot 9\cdot 10}\right)$

$x\:=\:70.52^{\circ }$

Therefore angle YXZ is 70.52 degrees

7 0

3 years ago

Is 99,782,829 divisible by 3? HELP ME PLZ

Zinaida [17]

Answer:

Yes, answer is 33260943 .

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What's 0.64 divided by 4 using standard algorithm

REY [17]

https://www.engageny.org/file/.../math-g5-m1-topic-f-lesson-14.docx?...

8 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Keith_Richards [23]

Answer: $\bold{D.\ \bigg(-\infty, \dfrac{ln\ 4}{0.2}\bigg)}$

Step-by-step explanation:

$y=\dfrac{c}{1+ae^{-rx}}\qquad \text{where growth rate increases from}\ -\infty\ to\ \dfrac{ln\ a}{r}$

$f(x) = \dfrac{15}{1+4e^{-0.2x}}\qquad \rightarrow \qquad a=4, r=0.2$

$\text{So, the growth rate increases over the interval}\ \bigg(-\infty, \dfrac{ln\ 4}{0.2}\bigg)$

4 0

4 years ago