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Xelga [282]
3 years ago
7

Determine if the two triangles are congruent. If they are, how you know.

Mathematics
2 answers:
Scilla [17]3 years ago
4 0

Answer:

not enough info

Step-by-step explanation:

you know that 2 angles are congruent. the third angle is right so they are congruent. so you have 3 angles that are congruent. AAA doesn't prove triangle congruence because the sides could be any length and still have congruent angles.

Katena32 [7]3 years ago
3 0

Answer:

ASA because there's two angles and a side

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A rectangular table top measures 7/9 of a meter long by 5/4 of a meter wide.<br> What is its area?
Rzqust [24]

Answer:

35/36 sq meters

Step-by-step explanation:

7/9 x 5/4 = 35/36 sq meters

8 0
2 years ago
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Can anybody help with this pls :)
klasskru [66]

Answer:

54 degrees

Step-by-step explanation:

4x + 6 + 11x - 6 = 180

Then solve

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3 years ago
Are y=2x+6 and 6t=2x+9 perpendicular
babymother [125]

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The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept. Using the slope-intercept form, the slope is 2 2 . The equation of a perpendicular line to y=2x+9 y = 2 x + 9 must have a slope that is the negative reciprocal of the original slope.

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4 0
3 years ago
A circle has the same perimeter as a square with the side length 8cm. What is the circle radius
seraphim [82]

side length of square = 8

perimeter of square = 4*(side length) = 4*8 = 32

perimeter of square = perimeter of circle = circumference = 32 cm

circumference formula is

C = 2pi*r

32 = 2pi*r .... plug in the given circumference

32/(2pi) = (2pi*r)/(2pi) .... divide both sides by 2pi

16/pi = r

r = 16/pi

r = 16/pi = the exact radius in terms of pi

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PLEASE HELP!!20 pts question
Molodets [167]

value of x is x=2, x=-2 and x=0

Step-by-step explanation:

Let a = x^2+4. Use a to find the solution for the following equation:

(x^2+4)^2+32=12x^2+48

Solving

(x^2+4)^2+32=12x^2+48

Taking 12 common from LHS

(x^2+4)^2+32=12(x^2+4)

Let a=x^2+4

(a)^2+32=12(a)\\a^2+32=12a\\a^2-12a+32=0

Factoring the equation

a^2-8a-4a+32=0\\a(a-8)-4(a-8)=0\\(a-8)(a-4)=0\\a-8=0\,\,and\,\,a-4=0\\a=8\,\,and\,\,a=4\\

Putting value of a i.e x^2+4

x^2+4=8\,\,and\,\,x^2+4=4\\x^2=8-4\,\,and\,\,x^2=4-4\\x^2=4\,\,and\,\,x^2=0\\Taking\,\,square\,\,root\,\,at:\\x=\pm 2\,\,and\,\,x=0\\

So, value of x is x=2, x=-2 and x=0

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

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