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3 years ago

3x+2y=6 how do i do this question i do not umderstand

Mathematics

2 answers:

agasfer [191]3 years ago

6 0

Answer:

You cannot.

Step-by-step explanation:

In order to solve for two variables, you need a system of equations, meaning at least two equations with the same two variables.

You cannot solve for x and y with just one equation as there will be an infinite range of solutions.

Let's say that there was a second equation, like:

x + 2y = 4

You could isolate the x (x = 4 - 2y), then substitute this value in the first equation:

3(4 - 2y) + 2y = 6

12 - 6y + 2y = 6 (expanded)

12 - 4y = 6

4y = 6

y = 6/4 = 3/2 (reduced)

Then, you plug this value of y into the x equation:

x = 4 - 2(3/2)

= 4 - 3

= 1

This is how you would solve it if you had another equation/a system of equations.

Hope this helps!

tatiyna3 years ago

4 0

Answer:

You would have to put this into a slope intercept form.

Step-by-step explanation:

Here's the step on how to do it:

1. 2y = -3x +6 (You subtract 3x from both sides)

2. y= -3/2x + 3 (Now you divide both sides by 2)

y = -3/2x +3 is your answer.

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Which logarithmic equation is equivalent to the exponential equation below? E^a=60

Gala2k [10]

Answer:

Step-by-step explanation:

e is the base of the natural log system.

take the natural log of both sides.

ln(e^a) = ln(60) The power can come down

a ln(e) = ln(60) The natural log of e = 1

a * 1 = ln (60)

a = ln(60)

8 0

4 years ago

I don’t understand what to do on these question, some help would be nice (trigonometry)

Bumek [7]

Step-by-step explanation:

> find the angle of center circle:

cos~¹ 5/(5+12) = cos~¹ 5/17 = 72°

so the sector area of the shaded

region =

(360-72)/360 × 3.14 × 5²

= 288/360 × 78.5

= 62.8

> the height of triangle (red Line) =

4×tan 72° = 4× 3.078 = 12.31

the height of pyramid (green

Line) = √12.31²-8.5² =√74.16

= 8.61

so the volume of pyramid =

⅓×(17×8)×8.61 = 390.32

8 0

3 years ago

What is the circumference of the given circle in terms of pi 12in ( 1 point?

mina [271]

The circumference of a circle is calculated through the equation,
C = 2πr
where C is circumference and r is radius. For this item, I assume that 12 in is the radius such that,
C = 2π(12 in) = 24π
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8 0

4 years ago

Read 2 more answers

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.