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bezimeni [28]
3 years ago
13

Can someone PLEASE HELP!!!

Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

Answer:

x = 15 cm

Step-by-step explanation:

Use Pythagorean thm:

9² + 12² = x²

81 + 144 = x²

225 = x²

√225 = √x²

15 = x

Hope this helped :)

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A classmate simplified a rational expression below
lara31 [8.8K]
<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

\:1-2x-4=x^2-x-2

-2x-3=x^2-x-2\:\:

0=x^2-2x-2\:\:

0=\left(x-1\right)\left(x-1\right)

x=1

<u><em>Identifying the Main Error</em></u>

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)   ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u>

<u><em /></u>\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)<em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)

\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

1-\frac{2}{x-2}=\frac{x+1}{x+2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)

1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)

\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

x^2-2x-8=x^2-x-2

x^2-2x-8+8=x^2-x-2+8

x^2-2x=x^2-x+6

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3 0
3 years ago
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Step-by-step explanation:

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It is given that the formula of discriminant is, D = b² - 4ac where a&b&c represent the number of the equation, ax²+bx+c = 0 :

x² + 14x + 13 = 0

D = b² - 4ac

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Answer:

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