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3 years ago

Please help me? I am confused.

Mathematics

2 answers:

Sergio [31]3 years ago

3 0

Answer:

It's a photo of the problem. It's not a spam. Just so you could be sure. ;-)

Have a good day

Sveta_85 [38]3 years ago

3 0

Answer:

x=4

Step-by-step explanation:

7-2x=2(x-4)-1

7-2x=2x-8-1

7-2x=2x-9

-2x on both sides which makes

7-4x=-9

-7 on both sides which makes

-4x=-16

divide both sides by -4 and

x=4

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A decorator wants to line the bottom with through George with paper if the bottom each drawer measures 36“ x 20“ how many square

amm1812

The amount of paper that are needed to line the bottom of 3 drawers with paper is equal to 2,160 square inches.

<h3>How to determine the amount of paper?</h3>

First of all, we would calculate the area of the bottom of each drawer as follows:

Area = length × width

Area = 36 × 20

Area = 720 square inches.

Next, we would multiply this area by 3:

Total area = 720 × 3

Total area = 2,160 square inches.

Read more on area here: brainly.com/question/12940992

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<u>Complete Question:</u>

A decorator wants to line the bottom of 3 drawers with paper. If the bottom of each drawer measures 36 inches by 20 inches, how many square inches of paper are needed?

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2 years ago

What is the solution to 2x2+x+2=0

nikitadnepr [17]

$2x^2 + x + 2 = 0$

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Two solutions, complex conjugates.

8 0

3 years ago

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Ilya [14]

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3 years ago

Select the correct answer from each drop-down menu.

9966 [12]

Answer:

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Step-by-step explanation:

Given that :

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3 years ago

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Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

Please help me? I am confused.​

Please help me? I am confused.