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Ede4ka [16]
3 years ago
11

Which of the following are solutions to the quadratic equation? Check all that

Mathematics
1 answer:
Ket [755]3 years ago
3 0

Answer:

x=-2

Step-by-step explanation:

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Wich expression represent the sum of 59 and x
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I don't see the answers, but it would most likely be 59 + x.
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gail ran 4<img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D" id="TexFormula1" title="\frac{6}{10}" alt="\frac{6}{10}" ali
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which property of polynomial multiplication says that the product of two polynomials is always polynomial
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3 years ago
(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.
DaniilM [7]

Answer:

The answer is "\frac{2}{9} \  and \ \frac{1}{9}"

Step-by-step explanation:

In point a:

The requires  1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

\frac{1}{\binom{3}{1}}=\frac{1}{3} .

They can pick 1 Chunin form of the matter of national with the value:

\frac{1}{\binom{3}{1}}=\frac{1}{3} .

They have the option to pick 1 join from of the country team with such a probability: \frac{1}{\binom{3}{1}}=\frac{1}{3}

And we can make the country teams: 3! = 6 different forms. Its chances of choosing a team full in the process described also are:

6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: \frac{1}{\binom{3}{1}}=\frac{1}{3}

Its odds of choosing the same rank ninja in such a different country team are: \frac{1}{\binom{3}{1}}=\frac{1}{3}

The likelihood of choosing the same level Ninja from the residual matter of national is: \frac{1}{\binom{3}{1}}=\frac{1}{3} Therefore, all 3 selected ninjas are likely the same grade: 3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}

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3 years ago
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