All you have to do is write a positive number. let's say 4, then write a positive exponent (that's the tiny number in the right corner of the regular number) and then just write a positive exponent less than 4.
So 4 squared

4 0

3 years ago

Let g(x)=2x and h(x)=x^2+4 find the value. (hog)(a)

lisov135 [29]

In short, (h o g)(a) is just h( g(a) ).

so what we can do is simply get g(a) first and then plug that in h(x).

$\bf \begin{cases}
g(x)&=2x\\
h(x)&=x^2+4\\
(h\circ g)(a)&=h(~~g(a)~~)
\end{cases}
\\\\\\
g(a)=2(a)\implies g(a)=2a
\\\\\\
h(~~g(a)~~)\implies h(~~2a~~)=(2a)^2+4
\\\\\\
h(~~2a~~)=(2^2a^2)+4\implies h(~~2a~~)=4a^2+4$

8 0

4 years ago

Can someone help me plz

wolverine [178]

Answer:

75°

Step-by-step explanation:

Recall: SOH CAH TOA

Reference angle = ? = θ

Side length opposite to reference angle = 27

Hypotenuse length = 28

Apply SOH, which is: