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Zolol [24]
3 years ago
8

Somebody please help me.................​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Answer:

D. 1 x 8

Step-by-step explanation:

7/8 rounds up to 1

8 1/10 rounds down to 8

so you're left with the numbers 1 and 8

this means your answer is D

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If parallelogram ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A' lie?
LuckyWell [14K]
D (-4 , -1)
relflected over x-axis= (4 , 1)
180 degrees= (-4 , -1)
6 0
3 years ago
The box-and-whisker plot describes the scores of golfers in a recent tournament.
romanna [79]
The minimum score was 70.

On a box-and-whisker, the dot on the left end is the lowest value.
The first line on the left is the lower quartile.
The second line is the median.
The third line is the upper quartile.
And finally, the dot on right end is the highest value. 

Hope I could help :) 
3 0
3 years ago
Doug entered a canoe race
kenny6666 [7]

Answer:

he can row 2 miles in an hour

Step-by-step explanation:

When canoeing it takes about 20-30 minutes to row atleast 1 hour there are 2 sets of 30 minutes in an hour meaning he can row 2 miles

7 0
3 years ago
Lisa ran 1/2 of a mile John R and 242 Mi what's girl ran further
julia-pushkina [17]

The fraction that has been given illustrates that the person who ran further is Jane.

<h3>How to solve fraction</h3>

Your information isn't complete. Therefore, an overview of the fraction will given.

Let's assume that Lisa ran 1/2 of a mile and Jane ran 3/4 of a mile. In order to know who ran more, you can convert the fraction to percentage.

This will be:

Lisa = 1/2 × 100 = 50%

Jane = 3/4 × 100 = 75%

Therefore, Jane ran more.

Learn more about fractions on:

brainly.com/question/78672

4 0
2 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
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