Answer:
I cannot not give the correct solution, need more context. How many children are there, how many adults are in the family? So I will explain in my explanation.
Step-by-step explanation:
If more context were given, for example:<em> 2 adults and 2 children.</em>
Then the bakers would have bought 2 adult tickets for ___ each
Then the bakers would have bought 3 children's tickets for ___ each
So using what we know we can create an equation:
<em>2A+3C=28</em>,<em> </em>
meaning 2 adult tickets plus 3 children's tickets costs a total of $28.
So we divide 28 by 5, which is the total amount of tickets.
28/5=5.6
So to figure the cost of children's tickets multiply the cost by amount.
3*$5.6=$16.8, C=16.8
To figure out the cost of the adults tickets multiple the cost by the amount.
2*$5.6=$11.2, A=11.2
a) the bakers would have bought <u>2</u> adult tickets for <u>5.6</u> each.
b) the bakers would have bought <u>3</u> children's tickets for <u>5.6</u> each.
Answer:
If the equation is 3^x=n (it isnt showing up properly)
Part A: any number greater than 1 will work. Say 2.
Part B: any number less than or equal to 1.
Step-by-step explanation:
If you set x=2, 3^2=9 9>3
If you set x=0, 3^0=1 1<3
Answer:
1. 5 + y = 7
⇒ y = 7 - 5
⇒<u>y = 5</u>
2. 3.8 = a + 2.5
⇒ a = 2.5 - 3.8
⇒ <u>a = -1.3</u>
3. 5 + p = 9 1/3
⇒ p = 9 1/3 - 5
⇒ p = 28/3 - 5
⇒ p = 28/3 - 15/3
⇒ p = 13/3
⇒<u> </u><u>p = 4 1/3</u>
Slope/gradient = 5
y= MX + C
(-6,-26)
-6 is x1 and -26 is y1
so therefore y= 5x -26
Answer:
A) C1 = 0.00187 m = 0.187 cm, C2 = 0.0062 m = 0.62 cm
B) A sample of how the graph looks like is attached below ( periodic sine wave )
C) w =
is when the amplitude of the forced response is maximum
Step-by-step explanation:
Given data :
mass = 5kg
length of spring = 10 cm = 0.1 m
f(t) = 10sin(t) N
viscous force = 2 N
speed of mass = 4 cm/s = 0.04 m/s
initial velocity = 3 cm/s = 0.03 m/s
Formulating initial value problem
y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m
spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m
f(t) = 10sin(t/2) N
using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion
the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)
A) finding the solution of the initial value
attached below is the solution and
B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like
C attached below