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zzz [600]
2 years ago
7

two joggers run 8 miles north and then 5 miles west. what is the shortest distance, to the nearest tenth of a mile, they must tr

avel to return to their starting point? round to the nearest tenths place
Mathematics
1 answer:
Rudiy272 years ago
3 0
A² + b² = c²

c² = 8² + 5²

c² = 89

c = √89

c = 9.4 miles

Answer: 9.4 miles
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Point I is on line segment HJ. Given HJ = 15 and IJ<br> HI.<br> 10, determine the length
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Answer:

Point I is on line segment HJ; which means HI and IJ are equal.

HJ = 15

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Finding the length of HI, given the above statements:

Length of HI = 10 (reason: HI and IJ are congruent)

8 0
3 years ago
Solve the system by elimination 1: x+5y-4z=-10, 2x-y+5z=-9, 2x-10y-5z=0 .. . 2. Solve the system by substitution: 2x-y+z=-4, z=5
Kryger [21]
1 )
1st and 2nd equation (multiply 1st by -2 ):
-2x - 10 y + 8 z = 20
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---------------------------
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1st and 3rd:
- 2 x - 10 y + 8 z = 20
   2 x - 10 y - 5 z = 0
-----------------------------
         - 20 x + 3 z = 20  /  * 11
        ----------------------------------
         220 y - 260 z = -220
        - 220 y + 33 z = 220
        ------------------------------
                       z = 0,      y = -1,        x = - 5
2 )  
       2 x - y + 5 = -4
       - 2 x + 3 y - 5 = - 10
       Substitution: y = 2 x + 9
       - 2 x + 3(2 x + 9 ) = -5
        4 x = - 32,          x = -8,    y = -7,   z = 5
3 )
      x + y + z = 11
   1.5 x+3 y +1.5 z = 21
      x = 2 y
   ------------------------
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      6 y + 1.5 z = 21
    ------------------------
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       6 y + 1.5 z = 21
      ------------------------
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yawa3891 [41]
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Answer:

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