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3 years ago

Can someone help me?

Mathematics

2 answers:

Norma-Jean [14]3 years ago

8 0

Answer: 26

Step-by-step explanation:

32-6 = 26

Bezzdna [24]3 years ago

4 0

X+6=32
12+x=24
X-8=11
X-9=5
X+6=7
X-(-4)=-18

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Simplify − 2/3 − 3/5 .

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3 years ago

A dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 pe

puteri [66]

Answer:

The correct option is B. 23%

Step-by-step explanation:

Let the event that patient brushes his teeth at least twice a day is denoted by A

So, P(A) = 0.83

Let the event that patient flosses daily is denoted by B

So, P(B) = 0.47

Now, it is given that 19 percent patients brush at least twice a day and floss daily.

⇒ P(A and B) = 0.19

Now, we need to find conditional probability of occurring event B given A has occurred.

$\implies P(B|A) =\frac{P(A\: and\: B)}{P(A)}\\\\\implies P(B|A) = \frac{0.19}{0.83}\\\\\implies P(B|A) = 0.2289\approx 0.23$

Hence, Nearest required percentage = 23%

Therefore, The correct option is B. 23%

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3 years ago

Read 2 more answers

Caroline resting heart is 52 beats per minute (bpm). When she starts running her heart rate increases 1.25% each second until it

horsena [70]

Answer:74.55 beat per minute

Step-by-step explanation:

Given

Heart beat is 52 beat per minute

i.e. $B=\frac{52}{60}$ beat per sec

If heart rate is increases 1.25 % each sec

suppose B is the heart beat at first second therefore heat beat at 2 nd second

$B_2=B+1.25 \% B$

$B_2=B(1+1.25 \% )$

For 3 rd sec

$B_3=B(1+1.25\%)+1.25\%B(1+1.25\%)$

$B_3=B(1+1.25\%)^2$

similarly for 3 sec

$B_{30}=B(1+1.25\%)^{29}$

$B_{30}=1.433B$

$B_{30}=1.242\ \text{beat per second }$

$B_{30}=74.55\ \text{beat per minute}$

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3 years ago

The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did

Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

$P(fatigue \left | \right drug)$ = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

$P(A \, and \, B)= P(A)\times P(B\left | \right A )$

From the options, we have;

$P(fatigue \left | \right drug)$ = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)× $P(fatigue \left | \right drug)$

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

$P(fatigue \left | \right drug)$ = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0

3 years ago

Can someone help me?​

Can someone help me?