I’m pretty sure it is c.
let me know if i’m wrong:)
Answer:
The statements that must be true are:
XY and JK form four right angles ⇒ B
XY ⊥ JK ⇒ C
JP = KP ⇒ E
m∠JPX = 90° ⇒ F
Step-by-step explanation:
From the given figure
∵ Line XY is the perpendicular bisector of the line segment JK
→ That means line XY is the line of symmetry of the line segment JK
∴ XY ⊥ JK ⇒ C
∵ XY ∩ JK at point P
∴ P is the midpoint of JK
∵ XY ⊥ JK
∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles
∴ XY and JK form four right angles ⇒ B
∵ The measure of the right angle is 90°
∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°
∴ m∠JPX = 90° ⇒ F
∵ P is the midpoint of JK
∴ JP = KP ⇒ E
For two line segments to be parallel, their slopes must be equal.
Therefore slope of AB must be equal to slope of CD
which is, option 3
<span> (y4-y3)/(x4-x3)=(y2-y1)/(x2-x1)</span>
