Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50
<span>=( r^2+7r+10)/3 (3r-30)/(r^2-5r-50) </span>
<span>=(r+2)(r+5)/3 3(r+10)/ (r-10)(r+5) </span>
<span>=3 (r+2)(r+5)(r+10)/3(r-10)(r+5) </span>
<span>=(r+2)(r+10)/(r-10)</span>
Answer:
2/3
Step-by-step explanation:
Answer:
The area that she painted = 896 mm^2
Step-by-step explanation:
Given:
The given figure is a pyramid with square base.
Here we need to find the surface area of the figure that need to be painted.
Surface area of a square pyramid = (S×S) + 2×S×L square.units
Where, S = side of the base L = slant height of the pyramid.
Now we have to plug in the given values.
Here S = 14, L =25
Plug in these values into the formula
= (14*14) + 2*14*25
= 196 + 700
= 896 mm^2
The area that she painted = 896 mm^2
Hope this will helpful.
Thank you.
Answer:
20-12-6=2
Step-by-step explanation:
why is this in college math bruh
