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Kaylis [27]
2 years ago
15

Find the equation of a line that contains the points (−4,8) and (7,−6). Use fractions in your response, not decimals.

Mathematics
1 answer:
Ierofanga [76]2 years ago
4 0

Answer:

Step-by-step explanation:

<h3>Equation of line in slope y-intercept form: </h3>

  (-4,8) ;  x₁ = -4  & y₁ = 8

  (7,-6)  ; x₂ = 7   & y₂ = -6

\sf \boxed{Slope=\dfrac{y_2-y_1}{x_2-x_1}}

           \sf =\dfrac{-6-8}{7-[-4]}\\\\  =\dfrac{-14}{7+4}\\\\=\dfrac{-14}{11}

Equation of line:  

               \sf y-y_1=m(x-x_1)

    y - 8 = \dfrac{-14}{11}(x -[-4])\\\\y- 8 = \dfrac{-14}{11}(x+4)\\\\y -8 = \dfrac{-14}{11}x-\dfrac{14*4}{11}\\\\   y = \dfrac{-14}{11}x-\dfrac{56}{11}+8\\\\   y =\dfrac{-14}{11}x-\dfrac{56}{11}+\dfrac{88}{11}\\\\y=\dfrac{-14}{11}x+\dfrac{32}{11}

   

       

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