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MA_775_DIABLO [31]
3 years ago
12

What is 5 Left-bracket cosine (StartFraction pi Over 4 EndFraction) + I sine (StartFraction pi Over 4 EndFraction) right-bracket

raised to the 3rd power?

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0

Answer:

C

Step-by-step explanation:

I took it on edg 2020

Ivan3 years ago
3 0

Answer:

c

Step-by-step explanation:

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A building in the shape of a pyramid was recently built. Each side of the pyramid’s square base has a length of 40 feet and the
Alex

Answer:32,000ft^3

Step-by-step explanation:

3 0
2 years ago
PLEASE HELP A rectangular region is removed from another rectangular region to create the shaded region shown below. Find the ar
Mars2501 [29]
<h3>Answer:  shaded region has area 107 square feet</h3>

================================================

Work Shown:

A = area of larger rectangle

A = length*width = 9*15 = 135 square feet

B = area of smaller rectangle

B = length*width = 7*4 = 28 square feet

C = area of shaded region

C = difference in areas of A and B

C = A - B = 135 - 28 = 107 square feet

4 0
3 years ago
Cerebral $500 for four years at 3% interest compounded annually use the formula to calculate the total amount she will have to p
Black_prince [1.1K]
Since we're doing compound interest for four years it will be simpler than daily.
In case you didn't know the formula, here it is: A = P (1 +r/n)^(nt)
now lets substitute.
A = 500 (1 + 0.03)^4
A = 500 (1.03)^4
A = 500 (1.12550881)
A = 562.754405
Since that decimal is too big for cash, let's round it. Notice that the number after 5 is lower than 5. Thus the first two numbers stay the same and the final answer will be..
A = 562.75
Hope this helps :3
4 0
3 years ago
Mike is looking for a loan. He is willing to pay no more than an effective rate of 8.000% annually. Which, if any, of the follow
RoseWind [281]
If Mike is willing to pay no more than an effective rate of 8.000% annually, the loans that meet his criteria are loan X and loan Z. Of those two, the lowest would be loan X.  I hope the answer will help you :)
8 0
3 years ago
Read 2 more answers
on a certain planet, objects weight about 7/12 of what they weigh on earth. an object weights 13 5/12 pounds on the planet. solv
Cloud [144]
Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is <span>7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.


</span>
8 0
3 years ago
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