3 years ago

9^5•9^8 rewrite the following expression using each base only once

Mathematics

1 answer:

alina1380 [7]3 years ago

7 0

Your answer would be 9^13

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Assuming x > 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s

ehidna [41]

The answer is 104 x times the square root of 5 x

11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
 $11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245} *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\ \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\ \\ =11* \sqrt{5} * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\ \\ 
=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\ \\ 
=77x* \sqrt{5*x} +27x* \sqrt{5*x} = \\ \\ 
=77x \sqrt{5x} +27x \sqrt{5x} = \\ \\ 
=104x \sqrt{5x}$

4 0

3 years ago

Read 2 more answers

Can someone answer this question?

Ber [7]

I hope this helps you