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3 years ago

PLZ HLP

Mathematics

2 answers:

USPshnik [31]3 years ago

8 0

Answer:

Add 200 and 2

Arada [10]3 years ago

5 0

Answer:

its add 200 and 2 lol

Step-by-step explanation:

i did the assignment

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Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4

Vladimir79 [104]

Answer:

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ 2nd

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is $32y^{10}-24$

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ $32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ the same with the answer

∴ The expression $32y^{10}-24$ = 8( $y^{10}-3$ ) is completely factored

∵ The expression is $20y^{7}+10y^{2}$

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of $y^{7}$ and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ $20y^{7}+10y^{2}=10y^{2}(2y^{5}+1)$ ⇒ not the same with the answer

∵ The expression is $16y^{5}+12y^{3}$

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of $y^{5}$ and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ the same with the answer

∴ The expression $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ is completely factored

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ )

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$

3 0

3 years ago

Let T: Rn → Rn be an invertible linear transformation, and let S and U be functions from Rn into Rn such that

ipn [44]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

$T: 1 \ R^n \to 1 \ R^n$ is invertible lines transformation

$S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \ \varepsilon\ 1 R^n\\\\$

T is invertiable linear transformation means that is

$T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix$

and $\ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists$

Let

$V \varepsilon\ a\ R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v$

so,

$s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \ \forall \ \ v \ \ \varepsilon \ \ 1 R^n$

7 0

3 years ago

Y = x m= _______ b=_________

Airida [17]

Answer:

m =1 , b = 0

Step-by-step explanation:

y = mx +b

y = x

y = 1x + 0

m =1 , b = 0

6 0

3 years ago

Jenny is cooking a chicken for dinner. A chicken needs to be cooked for 40 mins per kilogram, plus an extra 20 mins. How long wi

goldenfox [79]

1.679 kg * (40 min)/(kg) + 20 min = 67.16 min + 20 min = 87.16 min

7 0

4 years ago

Which sequence of transformations would result in a figure that is similar, but not congruent, to the original figure? Select al

Aleksandr-060686 [28]

SIMILAR but NOT CONGRUENT
<span>a rotation about the origin of 50° followed by a dilation with a scale factor of 8
</span><span>a dilation with a scale factor of 0.6 followed by a translation of 2 units up

Congruent figures are equal measures. Similar figures do not have equal measures but have equal proportions.

I made a graph of the two triangles. Pls. see attachment.</span>

7 0

3 years ago