Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
Multiply 2/3 and your number. If you have a whole number, convert it to a fraction by putting it over a denominator of 1. When multiplying fractions, calculate numerator times numerator, then denominator times denominator. For example, to find two-thirds of 18, multiply 2/3 x 18/1 to get 36/3.
Answer:
C
Step-by-step explanation:
It should be 2/3 because there are 6 balls and two of them are green which gives the fraction 2/6 and can be reduced to 1/3
G(x) would have to be -->7 units.
The relationship between f(x) and s(x) where s(x)=af(x-b)+z is that g(x) is f(x) stretched by the reciprocal of a, b is the liar (all x values go up if b goes down and visa versa), and it moves up z units.
