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zalisa [80]
2 years ago
8

5m-3m+7n+2-5n please help​

Mathematics
2 answers:
ioda2 years ago
7 0

\\ \sf\bull\longmapsto 5m-3m+7n+2-5n

\\ \sf\bull\longmapsto 2m+7n-5n+2

\\ \sf\bull\longmapsto 2m+2n+2

\\ \sf\bull\longmapsto 2(m+n+1)

luda_lava [24]2 years ago
4 0

Answer:

\pmb{2(m+n+1)}

Step-by-step explanation:

  • 5m-3m+7n+2-5n

  • 2m+2n+2

  • 2(m+n+1)
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Determine the discount between the point(-4,2) and the line 4y=3×+6​
frozen [14]

Answer:

d = 14/5

Step-by-step explanation:

The point (-4,2) means that;

At x = -4, y = 2

Now general form of a linear equation is;

Ax + By + C = 0

We are given;

4y = 3x + 6​

Rearranging to the form of a linear equation gives;

3x - 4y + 6 = 0

Thus, A = 3, B = -4 and C = 6

Thus, at point (-4,2), distance between them is;

d = (3(-4) - 4(2) + 6)/√(3² + (-4)²)

d = -14/5

We will take the absolute value.

Thus; d = 14/5

6 0
3 years ago
Help....................................DDDDDDDDDDDDDDDDDDDDDDDDDDD
m_a_m_a [10]

Answer:

Step-by-step explanation:

a). Since, ΔABC ~ ΔWYZ

Their corresponding sides will be proportional.

\frac{AB}{WY}=\frac{BC}{YZ}= \frac{AC}{WZ}

\frac{194}{WY}=\frac{BC}{1}= \frac{130}{WZ}  --------(1)

By applying Pythagoras theorem in ΔABC,

AB² = AC² + BC²

BC² = AB² - AC²

BC² = (194)² - (130)²

BC² = 20736

BC = 144

From equation (1)

\frac{194}{WY}=\frac{144}{1}= \frac{130}{WZ}

\frac{194}{WY}=\frac{144}{1}

WY = \frac{194}{144}

WY = \frac{97}{72} = 1.35

\frac{144}{1}= \frac{130}{WZ}

WZ = \frac{130}{144}

WZ = \frac{65}{72} = 0.90

b). tan(A) = \frac{\text{Opposite side}}{\text{Adjacent side}}

               = \frac{144}{130}

               = \frac{72}{65}

Since, ΔABC ~ ΔWYZ,

∠A ≅ ∠W

Therefore, tangent of angle A and angle W will measure \frac{72}{65}.

8 0
3 years ago
15. Solve for the variable. Show all work.
MrRissso [65]
Add 15 and 9, then subtract that by 87. 63 should be your answer.
5 0
3 years ago
Write a ratio for “45 and 20 to 6”
9966 [12]

Answer: I can't do ratios, Sorry!

Step-by-step explanation:

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=5x%20%7B%7D%5E%7B2%7D%20%20%2B%202x%20-%203%20-%20px%20-%20p" id="TexFormula1" title="5x {}^{2
Jlenok [28]

Answer:

5x² + 2x - 3 - px - p

= 5x² + 5x - 3x - 3 - p(x + 1)

= 5x(x + 1) - 3(x + 1) - p(x + 1)

= (x + 1)(5x - 3 - p)

5 0
3 years ago
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