The hypotenuse can be solved by this formula. X^2 = 6^2 +6^2
X^2=64
Usually you cut it down to 8 but it wants the squared form so 64.
Answer: 3y⁴(y² + 5)(y - 1)(y + 1)
<u>Step-by-step explanation:</u>
3y⁸ + 12y⁶ - 15y⁴
= 3y⁴(y⁴ + 4y² - 5)
= 3y⁴(y² + 5)(y² - 1)
= 3y⁴(y² + 5)(y - 1)(y + 1)
Answer:
Step-by-step explanation:
Answer:
p(x) = (5x - 1) (x + 3)
Step-by-step explanation:
I apologize if I couldn't answer correctly, the question was a bit hard to understand because of the formatting.
Also I didn't see my answer in the list of answer choices but here it is:
if the polynomial has zeros at 0.2 and -3 the equation would have to be:
p(x)=(x-0.2)(x+3)
This is because plugging either of those numbers into the polynomial would cause it to equal 0.
(x-0.2) can be simplified by multiplying everything in the parenthesis by 5, getting rid of all of the decimals, making the final answer:
p(x) = (5x - 1) (x + 3)
