Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
Answer:
IDK
Step-by-step explanation:
(-3,2) (0,0) i think. it’s been a whole
A.)The equation is 24 + 8=32. Twice of the amount of 24 is 6 times the amount of 8. 24 x 2= 48. 48/6=8.
B.) X +Y=32 and 2x=6y
Shade 3 bars and you'll get it right
