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mash [69]
3 years ago
10

Answer please it is needed

Mathematics
2 answers:
I am Lyosha [343]3 years ago
8 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The slope-intercept form :

y = mx + b

Thus :

y =  - 4x +  \frac{9}{4}  \\

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Bond [772]3 years ago
6 0
Y = mx + b
y = -4x + 9/4
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Fishermen fishing for spiny lobster are allowed to keep only lobsters with a carapace length of 3.25 inches or longer. (Than car
ser-zykov [4K]

Answer:

16%

Step-by-step explanation:

First we start by solving for the z score

We have the following information

x = 3.25

Standard deviation = sd = 2.25

Mean = 5.50

Z = (x - mean)/sd

z = 3.25 - 5.50/2 25

z = -1.00

If we look this up in the standard normal distribution table,

P(z<-1.00) = 0.1587

Which when approximated gives us

16%

Therefore approximately 16% of lobsters will have to be returned back to the sea.

4 0
3 years ago
Find the circumference and area of a circle with a diameter of 14 inches. Leave your answers in terms of pi.
IRINA_888 [86]

Step-by-step explanation:

step 1. The circumference (c) of a circle is the diameter of a circle x pi. c = d(pi) = 14pi.

step 2. The area (A) of a circle is the radius of a circle squared x pi. The radius of a circle is 1/2 x the diameter. A = (14/2)^2(pi) = 49pi.

4 0
3 years ago
All of the following represent the same function except ____.
Whitepunk [10]

Answer:

I believe it's C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form of the line that passes through (-1,-3) and is parallel to the graph of y=4.
strojnjashka [21]
Use the point slope equation: y - y1 = m(x - x1)

(-1, -3); m = 4
Plug these numbers in.

y - (-3) = 4(x - -1)
y + 3 = 4x + 4
y = 4x + 1
3 0
3 years ago
Read 2 more answers
An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
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