The conditional probability illustrates that's there's a 2/8 that the event A occurs.
<h3>How to illustrate the probability?</h3>
It should be noted that probability simply means the likelihood of the occurence of an event.
In this case, it can be delivered that P(AID) and P(DIA) aren't equal.
Hence, P(D|A) has event A as its given event, resulting in 2/8 for a probability.
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Let's see if we can't be logical here......Pick a formula and see what it yields. For example, choose D.
For n = 1 ---> -1 x 4^1 ----> -1 x 4 = -4, when the correct value is 1. Therefore D is out.
Try C. For n = 1 ---> 1 x 4^(1-1) ---> 1 x 4^0 ----> 1 x1 ---> 1, So it is correct for n =1. How about
n=2? 1 x 4^(2-1) = 1 x 4^1 = 1 x 4 = 4, when the correct answer is -4. Therefore C is out
I'm sure you can do the remaining two choices....
Answer:
You earned $45.50 taking care of your neighbor's dog.
Step-by-step explanation:
Add 38.75 + 25. You get 63.75.
Subtract 63.75 - 18.25. That is how you get your answer. I hope this helps.
Sorry i cant tell which is 1 through 6
