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Valentin [98]
3 years ago
11

Square root of: (q+3)*(q+6)

Mathematics
1 answer:
AnnyKZ [126]3 years ago
3 0
To factor (q+3)(q+6)
           q^2+6q+3q+18
              q^2+9q+18
              (q+9)(q+2)
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I NEED THIS ASAP- Point A is located at (-5, -8). Point A is reflected across the X-axis to create point B. What is point B?
Rasek [7]

Answer:

(5,-8)

Step-by-step explanation:

if it is reflected across the X axis and this is in quadrant 3 that means if it was reflected it would fall in quadrant 2

6 0
3 years ago
The line with a slope of 1/3 and a y- intercept of -15 intersects the line passing through which of these pairs of points? Selec
padilas [110]
<h2>B</h2><h2>C</h2><h2>E</h2><h2></h2><h3>are the correct answers!</h3><h3></h3><h3></h3><h3></h3><h3></h3><h3></h3><h3><em>Let me know if I'm wrong!</em></h3>
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3 years ago
What is the solution
omeli [17]
5x + 6y = 272

if you need the y-intercept
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7 0
3 years ago
Please Help!!<br><br>Use Euler’s formula to write in exponential form.
LekaFEV [45]

Answer:

C, 4e^{i(7\pi/4)}

Step-by-step explanation:

To remind you, Euler's formula gives a link between trigonometric and exponential functions in a very profound way:

e^{ix}=\cos{x}+i\sin{x}

Given the complex number 2\sqrt{2}-2i\sqrt{2}, we want to try to get it in the same form as the right side of Euler's formula. As things are, though, we're unable to, and the reason for that has to do with the fact that both the sine and cosine functions are bound between the values 1 and -1, and 2√2 and -2√2 both lie outside that range.

One thing we could try would be to factor out a 2 to reduce both of those terms, giving us the expression 2(\sqrt{2}-i\sqrt{2})

Still no good. √2 and -√2 are still greater than 1 and less than -1 respectively, so we'll have to reduce them a little more. With some clever thinking, you could factor out another 2, giving us the expression 4\left(\frac{\sqrt{2}}{2} -i\frac{\sqrt{2}}{2}\right) , and <em>now </em>we have something to work with.

Looking back at Euler's formula e^{ix}=\cos{x}+i\sin{x}, we can map our expression inside the parentheses to the one on the right side of the formula, giving us \cos{x}=\frac{\sqrt2}{2} and \sin{x}=-\frac{\sqrt2}{2}, or equivalently:

\cos^{-1}{\frac{\sqrt2}{2} }=\sin^{-1}-\frac{\sqrt2}{2} =x

At this point, we can look at the unit circle (attached) to see the angle satisfying these two values for sine and cosine is 7π/4, so x=\frac{7\pi}{4}, and we can finally replace our expression in parentheses with its exponential equivalent:

4\left(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}\right)=4e^{i(7\pi/4)}

Which is c on the multiple choice section.

4 0
4 years ago
El ancho de un rectángulo es 15 pies menos que
Karolina [17]

Answer:

II. Longitud, L = 70 metros.

I. Ancho = 55 metros.

Step-by-step explanation:

Deje que la longitud del rectángulo sea L.

Deje que el ancho del rectángulo sea W.

Dados los siguientes datos;

Perímetro del rectángulo = 250 m

Traduciendo el problema verbal a una expresión algebraica, tenemos;

W = L - 15

Matemáticamente, el perímetro de un rectángulo viene dado por la fórmula;

P = 2 (largo + ancho)

250 = 2 (L + L - 15)

250 = 2 (2L - 15)

250 = 4L - 30

4L = 250 + 30

4L = 280

L = 280/4

Longitud, L = 70 m

Para encontrar el ancho;

W = L - 15

W = 70 - 15

Ancho = 55 m

3 0
3 years ago
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