Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
So you first make 1 7/9 into 16/9
then you do 16/9 - 4/9 which equals to 12/9 then you simplify and get 4/3 then simplify again into 1 1/3
The answer is 0
Let me tell you why
first plug in the numbers
.5(18+14)-(18-14)^2
(9+7)-(4)^2
16-16
0
They are both correct becuase lets say it was a shirt that was $30 and it was 30% off. For Jasani it would be 30 * 0.7 which equals $9 then you would subtract this 30 - 9 = 21. For Hanna it would be 30 - 0.3(30) which equals $21. So in the end they are both correct!
Answer:
they would both be 61°
Step-by-step explanation:
when the angles make out a straight line it equals to 180 and 180 subtracted to 119 comes out to 61 and both b and c are vertical angles which would make them congruent
