Answer:
hole at x=-3
Step-by-step explanation:
The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)
The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.
So anyways we have (x+3)/(x^2-9)
= (x+3)/((x-3)(x+3))
Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.
Answer:
b. When you divide both sides by 2x = 6x it could lead us to think that there is no solution while, in fact, the solution is x = 0.
Step-by-step explanation:
The solution is correct up to the step 2x = 6x
2x = 6x
Subtract 2x from both sides.
0 = 4x
Divide both sides by 4.
x = 0
You cannot divide both sides by x since x could be zero, and in fact, it is.
Answer: b. When you divide both sides by 2x = 6x it could lead us to think that there is no solution while, in fact, the solution is x = 0.
Answer:
C
Step-by-step explanation:
(3^5)^2 = 3^10
(8^2)^5 = 8^10
therefore
(3/8)^10
