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Scorpion4ik [409]
3 years ago
10

Help meeee please or I'm going to fail school

Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0

Answer:

thh

Step-by-step explanation:

kow [346]3 years ago
5 0

Answer: The is THH, or A.

Step-by-step explanation: The question directly ask for “at least two heads”, which no other answer contains two heads. Therefore, the answer is A.

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Rom4ik [11]
Go on this web operation calcularter

8 0
4 years ago
Sydney has a bag of stuffed animals containing, 1 elephant, 4 bears, 3 cats, and 2 dogs. If she randomly selects 1 stuffed anima
torisob [31]

Answer:

2/15

Step-by-step explanation:

Step one:

given data

sample space

1 elephant,

4 bears,

3 cats, and

2 dogs.

sample size= 1+4+3+2= 10

Required:

By selecting without replacement, the probability that she chooses a bear both times

Step two:

the first event= Pr(bear)= 4/10= 2/5

the second event, the sample size is now 9 and the number of bears is now 3

Pr(bear)= 3/9= 1/3

Hence, the probability that she chooses a bear both times

= 2/5*1/3

=2/15

3 0
4 years ago
The bad debt ratio for a financial institution is defined to the dollar value of loans defaulted divided by the total dollar val
vlabodo [156]

Answer:

Step-by-step explanation:

From the information given:

Consider X to be the random variable denoting the bad debt ratios for Ohio Bank.

Then, X \sim N ( \mu, \sigma ^2)

Thus the null hypothesis and the alternative can be computed as:

Null hypothesis:

H_o :  \mu \leq3.5\%

Alternative hypothesis

H_1 : \mu > 3.5\%

The type I and type II error is as follows:

Type I:

The mean bad debt ratio is > 3.5% when it is not

Type II:

The mean bad debt ratio is ≤ 3.5% when it is not.

The test statistics can be calculated by using the formula:

t = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}

where;

sample size n = 7

mean = 6+8+5+9+7+5+8 = 48

sample mean \overline x =\dfrac{48}{7}

\overline x = 6.86

sample standard deviation is :

s = \sqrt{\dfrac{\sum( x -\overline x)^2}{n-1}}

s = \sqrt{\dfrac{( 6 -6.86)^2+( 8-6.86)^2+  ( 5 -6.86)^2 + ...+( 7 -6.86)^2+ ( 5 -6.86)^2+( 8 -6.86)^2 }{7-1}}

s = 1.573

population  mean \mu = 3.5

Therefore, the test statistics is :

t = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}

t = \dfrac{6.86- 3.5}{\dfrac{1.573}{\sqrt{7}}}

t = \dfrac{3.36}{\dfrac{1.573}{2.65}}

t = \dfrac{3.36\times {2.65}}{{1.573}}

t = 5.660

At significance level of 0.01

t_{0.01} = 3.707  

P - value = P(T > 5.66)

P - value = 1 - (T < 5.66)

P - value = 1 - 0.9993

P-value = 0.0007

Therefore, since t_{0.01} < t , we reject the null hypothesis and conclude that the claim that the mean bad debt ratio for Ohio banks is higher than the mean for all financial institutions is true.

4 0
4 years ago
"At ​$1.29 million​, they closed last month for...26 percent above what they paid in​ 2007." How much did they pay in​ 2007?
Morgarella [4.7K]

Answer:  Amount that they paid in 2007 is 1.01 millions.

Step-by-step explanation:

Since we have given that

Number of millions paid last month = $1.29 millions

According to question, it was 26% above what they paid in 2007.

Let the amount paid in 2007 be x

So, our equation becomes,

\frac{100+27}{100}\times x=1.29\\\\\frac{127}{100}\times x=1.29\\\\1.27\times x=1.29\\\\x=\frac{1.29}{1.27}\\\\x=1.01\ millions

Hence, Amount that they paid in 2007 is 1.01 millions.

7 0
4 years ago
Read 2 more answers
Can someone please give me a good explanation of how to work this out! 15 points for a good answer.
Leya [2.2K]
  • Answer:

<em>= 26,(6)</em>

<em>≈ 26,7</em>

  • Step-by-step explanation:

<em>C = 5/9(F - 32)</em>

<em>= 5/9(80 - 32)</em>

<em>= 5/9(48)</em>

<em>= 5×48/9</em>

<em>= 240/9</em>

<em>= 26,(6)</em>

<em>≈ 26,7</em>

7 0
3 years ago
Read 2 more answers
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