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3 years ago

The quotient of a number divided by 4 is -12. What is the number? _____

Mathematics

1 answer:

juin [17]3 years ago

8 0

Answer:

-48

Step-by-step explanation:

I'm Bigbrain

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_3x_13 =_7x+15 what is the an

Tema [17]

Answer:

Step-by-step explanation:

_3x_13 =_7x+15 what is the anSWER?

assuming that the underscore is a minus and you are looking for the x value.

-3x - 13 = -7 + 15

-3x = -7 + 15 + 13

-3x = 8 + 13

-3x = 21

x = -7

---------------

check

-3 * (-7) - 13 = -7 + 15

21 - 13 = 8

8 = 8

the answer is good

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2 years ago

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Three-billion one-hundred-fifty-two-million three-hundred-eight-thousand nine

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4 years ago

I don't understand!!

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4 years ago

Graph the line y=5/3x on the axes below using two points.

Oxana [17]

Answer:

I don't know the two coordinates but this would be the graph according to your equation.

Step-by-step explanation:

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3 years ago

Which point is on the circle centered at the origin with a radius of 5 units? Distance formula: StartRoot (x 2 minus x 1) square

Sergeeva-Olga [200]

Answer:

Option A) $(2,\sqrt{21})$

Step-by-step explanation:

The following information is missing in the question:

A. $(2,\sqrt{21})$

B. $(2,\sqrt{23})$

C. (2, 1)

D. (2, 3)

We are given the following in the question:

A circle centered at origin and radius 5 units.

We have to find the equation of a point that lies on the circle.

Let (x,y) lie on the circle.

Distance formula:

$d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Putting

$(x_2,y_2) = (x,y)\\(x_1.y_1) = (0,0)\\d = 5$

We get,

$5 = \sqrt{(y-0)^2 + (x-0)^2}\\\sqrt{x^2+y^2}=5\\x^2+y^2 = 25$

is the required equation of point on the circle centered at the origin with a radius of 5 units.

The point $(2,\sqrt{21})$ satisfies the given equation.

Verification:

$(2)^2 + (\sqrt{21})^2\\=4 + 21\\=25$

Thus, $(2,\sqrt{21})$ lies on the circle centered at the origin with a radius of 5 units.

7 0

4 years ago

Read 2 more answers