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Nikolay [14]
3 years ago
11

The blueprint of an aircraft carrier uses a scale of 1 inch = 120 feet. If the aircraft carrier is 9 1/10 inches long on the blu

eprint, find its actual length.
Mathematics
2 answers:
omeli [17]3 years ago
7 0

Answer:

(120*9) + (120/10) = 1080+12=1092

Step-by-step explanation:

Aleksandr-060686 [28]3 years ago
4 0

Answer:

Step-by-step explanation:

9.1 inches × (120 ft)/inch = 1092 ft

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We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.

First of all, we will draw a right triangle using our given information as shown in the attachment.  

We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.

We know that tangent relates opposite side of right triangle to adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

\text{tan}(29^{\circ})=\frac{88}{IJ}

IJ=\frac{88}{\text{tan}(29^{\circ})}

IJ=\frac{88}{0.554309051453}

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Upon rounding to nearest tenth, we will get:

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