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3 years ago

Add 7 to 5, then divide b by the result

Mathematics

2 answers:

LenKa [72]3 years ago

6 0

Answer:

you didnt say what b was but itd be 12/b

Step-by-step explanation:

Ahat [919]3 years ago

6 0

Answer:

b/12

Step-by-step explanation:

whats b?

7 + 5 = 12

so whatever b is, divide that by 12

b/12

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Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the gi

Lina20 [59]

Answer:

y=-4x-14

Step-by-step explanation:

Lines that are parallel would have the same slope, so the slope is

m= -4

Use point slope equation to solve for the slope intercept equation.

y-y1=m(x-x1)

m= -4

x= -3

y= -2

y-(-2)=-4(x-(-3))

y+2=-4x-12

y=-4x-14

5 0

3 years ago

What is 3533÷274737473

tensa zangetsu [6.8K]

3,533÷274,737,473=0.0000128595490139054

4 0

4 years ago

Read 2 more answers

Point T is the midpoint of . The coordinate of T is (0, 4) and the coordinate of J is (0, 2). The coordinate of H is: (0, 6) (0,

Anuta_ua [19.1K]

Point T is the midpoint of J and H.

x-coordinate is 0 for the three points.

y-coordinate of T is in the middle of the y-coordinate of J and the y-coordinate of H. So, y-coordinate of H has to be 6, because (6+2)/2=8/2=4.

Then point H is (0,6).

3 0

3 years ago

Solve for x in the equation 9- x/4=2

jeka57 [31]

Answer:

9-x/4=2

$\frac{36 - x}{4} = 2$

$36 - x = 2 \times 4$

$36 - x = 8$

$36 - 8 = x$

$28 = x$

$x = 28$

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3 years ago

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A small cube with side length 6y is placed inside a larger cube with side length 4/2. What is the difference in the

Leokris [45]

Answer:

Step-by-step explanation:

Side length of a small cube = 6y

Side length of a larger cube = 4x²

This small cube is placed inside a larger cube. We need to find the difference in the volume of the cubes.

Volume of small cube, $V_1=(6y)^3=216y^3$

Volume of lager cube,

$V_2=(4x^2)^3\\\\=64x^6$

Difference in the volume of the cubes,

$\Delta V=V_2-V_1\\\\=64x^6-216y^3$

We can simplify the above expression :

$\because \ (a^3-b^3)=(a-b)(a^2+ab+b^2)\\\\(4x^2)^3-(6y)^3=(4x^2-6y)((4x^2)^2+4x^2\times 6y +(6y)^2)\\\\=(4x^2-6y)(16x^4+24x^2y+36y^2)$

So, the difference in the volumes of the cubes is $(4x^2-6y)(16x^4+24x^2y+36y^2)$ .

3 0

3 years ago