So all you need to do if find the min of the function:
f(x)=0.04x^3-4x^2-176x
f'(x)=0.12x^2-8x-176
The only zero for this is x=84.105 <---first
Plug this into f(x) to get f(84.105)=-19300 <---second
A is the closest I got. My answer was 32.665 using thousandth place. I found the perimeter by adding up the lengths. I found all of the lengths by using pathat oran theorem.
