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attashe74 [19]
3 years ago
14

4/8 times 3/4 simplified pls and thank you

Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Answer:

3/8

Step-by-step explanation:

divide out the 4's and you are left with 3/8

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A Norman window is a rectangle with a semicircle on top. Suppose that the perimeter of a particular Norman window is to be 25 fe
Varvara68 [4.7K]

Answer:

Length =\frac{25}{4 + \pi} and Width = \frac{50}{4+\pi}

Step-by-step explanation:

This question is better understood with an attachment.

See attachment for illustration.

Given

<em>Represent Perimeter with P</em>

P = 25ft

Required

Determine the dimension of the rectangle that maximizes the area

First, we calculate the perimeter of the rectangular part of the window.

From the attachment, the rectangle is not closed at the top.

So, The perimeter would be the sum of the three closed sides

Where

Width = 2x

Length = y

So:

P_{Rectangle} = y + y + 2x

P_{Rectangle} = 2y + 2x

Next, we determine the circumference of the semi circle.

Circumference of a semicircle is calculated as:

C = \frac{1}{2}\pi r

From the attachment,

Radius (r) = x

So, we have:

C = \frac{1}{2}2\pi * x

C = \pi x

So, the perimeter of the window is:

P = P_{Rectangle} + C

P =2y + 2x + \pi x

Recall that: P = 25

So, we have:

25 =2y + 2x +\pi x

Make 2y the subject

2y = 25 - 2x - \pi x

Make y the subject:

y = \frac{25}{2} - \frac{2x}{2} - \frac{\pi x}{2}

y = \frac{25}{2} - x - \frac{\pi x}{2}

Next, we determine the area (A) of the window

A = Area of Rectangle + Area of Semicircle

A = 2x * y + \frac{1}{2}\pi r^2

A = 2xy + \frac{1}{2}\pi r^2

Recall that

Radius (r) = x

A = 2xy + \frac{1}{2}\pi x^2

Substitute \frac{25}{2} - x - \frac{\pi x}{2} for y in A = 2xy + \frac{1}{2}\pi x^2

A = 2x(\frac{25}{2} - x - \frac{\pi x}{2}) + \frac{1}{2}\pi x^2

Open Bracket

A = 2x * \frac{25}{2} - 2x * x - 2x * \frac{\pi x}{2} + \frac{1}{2}\pi x^2

A = 25x - 2x^2 - \pi x^2 + \frac{1}{2}\pi x^2

A = 25x - 2x^2 -  \frac{1}{2}\pi x^2

To maximize area, we have to determine differentiate both sides and set A' = 0

Differentiate

A' = 25 - 4x - \pi x

A' = 0

So, we have:

0  = 25 - 4x - \pi x

Factorize:

0 = 25 -x(4 + \pi)

-25 =-x(4 + \pi)

Solve for x

x = \frac{-25}{-(4+\pi)}

x = \frac{25}{4+\pi}

Recall that

Width = 2x

Width = 2(\frac{25}{4+\pi})

Width = \frac{50}{4+\pi}

Recall that:

y = \frac{25}{2} - x - \frac{\pi x}{2}

Substitute \frac{25}{4+\pi} for x

y = \frac{25}{2} - (\frac{25}{4+\pi}) - \frac{\pi (\frac{25}{4+\pi})}{2}

y = \frac{25}{2} - (\frac{25}{4+\pi}) - \frac{\frac{25\pi}{4+\pi}}{2}

y = \frac{25}{2} - (\frac{25}{4+\pi}) - \frac{25\pi}{4+\pi} * \frac{1}{2}

y = \frac{25}{2} - \frac{25}{4+\pi} - \frac{25\pi}{2(4+\pi)}

y = \frac{25(4+\pi) - 25 * 2 - 25\pi}{2(4 + \pi)}

y = \frac{100+25\pi - 50 - 25\pi}{2(4 + \pi)}

y = \frac{100- 50+25\pi  - 25\pi}{2(4 + \pi)}

y = \frac{50}{2(4 + \pi)}

y = \frac{25}{4 + \pi}

Recall that:

Length = y

So:

Length =\frac{25}{4 + \pi}

Hence, the dimension of the rectangle is:

<em></em>Length =\frac{25}{4 + \pi}<em> and </em>Width = \frac{50}{4+\pi}<em></em>

3 0
3 years ago
Tomas has a garden with a length of 2.45 meters and a width of 5/8 meters. Use benchmarks to estimate the area and perimeter of
Alchen [17]

Answer: The area is  1 1/4. The perimeter is 6.

Step-by-step explanation: 2.45 is about 2.5.   5/8 is about 1/2.  To find the area we need to multiply length times width.  2.5 is  2 and 1/2 which is 5/2. 5/2 times 1/2 is 5/4. To simplify it divide 5 by 4 which is 1 with remainder 1. 5/4 is 1 1/4. Therefore the area is 1 1/4 meters squared. To find the perimeter we have to add length + length + width + width. . 2.5 is the same thing as 2 1/2.  5/8 is about 1/2 if we use benchmarks.     2 1/2 + 2 1/2 +  + 1/2 + 1/2 is 6. The perimeter is 6.

5 0
3 years ago
Read 2 more answers
What is the area of the garden?
REY [17]

Answer:

sorry can't help need the coins

5 0
3 years ago
Negative five fourths divided by 3
rjkz [21]

Answer:

-5/12

Step-by-step explanation:

-5/4 / 3

Multiply by the reciprocal

-5/4 × 1/3

Multiply across

-5 × 1 = -5

4 × 3 = 12

-5/12

8 0
4 years ago
What is 120-40÷4×6 help please!
maks197457 [2]

120 - 40 \div 4 \times 6 \\ 120 - 10 \times 6 \\ 120 - 60 \\  = 60

7 0
3 years ago
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