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erica [24]
2 years ago
7

X - 10.2 > 5.3 PLSSSSSS HELP ME SOLVE THIS PROBLEM!!!!...

Mathematics
1 answer:
mamaluj [8]2 years ago
6 0

Answer:

x>15.5

Step-by-step explanation:

x - 10.2 > 5.3

Add 10.2 to both sides

x-10.2+10.2>5.3+10.2

Simplify getting the answer of

x>15.5

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5/6v+10=5 what is the answer
yulyashka [42]

Answer:

x= -3/2

Step-by-step explanation:

You would multiply both sides by 6x+10 and then that would give you 5-5)6x+10) and you would divide both sides by 5. This would give you 1=6x+10, you would then try to isolate the 6x giving you -6x=10-1  or -6x=9 and you would see if the solutions are in the defined ranges so x=-5/3 is NOT in the defined range but x=-3/2 is.

6 0
3 years ago
Quadrilateral ABCD is similar to quadrilateral EFGH. Find the measure of side EF
garri49 [273]

Answer:

EF = 6.6

Step-by-step explanation:

Since ABCD is similar to EFGH, then EH is similar to AD. So, we can solve by first dividing 12 by 2 (EH by AD). The quotient of this is 6. This tells us that quadrilateral EFGH is 6 times larger than quadrilateral ABCD, since they are similar. So, with this and the measurement of AB (which is similar to EF), we can now solve for EF. We simply multiply 1.1 (the measurement of AB) by 6 (how many times larger EFGH is compared to ABCD). The product of this is 6.6, our final answer.

3 0
3 years ago
What is the decimal representation of 1/8?
jarptica [38.1K]
Its A 0.125 because 0.125×8=1.000 or 1 full
6 0
3 years ago
Given the function defined in the table below, find the average rate of
AURORKA [14]

Answer:

Average rate of change = \frac{2}{5}

Step-by-step explanation:

Average rate of change of a function 'f' in the interval a ≤ x ≤ b is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

We have to find the average rate of change in the interval 20 ≤ x ≤ 65

From the table attached,

f(65) = 32

f(20) = 14

Average rate of change = \frac{32-14}{65-20}

                                        = \frac{18}{45}

                                        = \frac{2}{5}

Therefore, average rate of change in the given interval is \frac{2}{5} .

7 0
3 years ago
A restaurant uses 290 pounds of onions every 2 and a half weeks. If they continue to use onions at the same rate, how many pound
Archy [21]
290/2.5 = 116 pounds per week

116 * 6 = 696 pounds
4 0
2 years ago
Read 2 more answers
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