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Karo-lina-s [1.5K]

3 years ago

9

Help me with this please

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer:

the atom is 3737

Step-by-step explanation:

because it's right

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What is the equation of the following line? Be sure to scroll down first to see

VladimirAG [237]

Answer:

The full answer in the media.Good luck!

3 0

3 years ago

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

3 years ago

BRAINLIEST AND POINTS!!!<br><br> PLEASE EXPLAIN

timofeeve [1]

Answer:

Option C. $\$23,134.61$

Step-by-step explanation:

we know that

$A=\frac{P[(1+r)^{n} -1]}{r(1+r)^{n}}$

we have

$P=\$400$

$r=0.075/12=0.00625$

$n=6*12=72\ months$

substitute in the formula

$A=\frac{400[(1+0.00625)^{72} -1]}{0.00625(1+0.00625)^{72}}\\ \\A=\frac{226.446972}{0.009788}\\ \\A=\$23,134.61$

4 0

3 years ago

5 cups to 8 cups <br> identify the percent

KIM [24]

5/8=x/100
x=(5/8)(100)=500/8
x=62.5%

3 0

3 years ago

The lacrosse player shown passes the ball to a team member who is directly in

REY [17]

Step-by-step explanation:

jjjh jo v go if to uc do of fi to do of do of gp pic do pucho TCP usi pic of gp hi

7 0

3 years ago