Rearrange equation.h=-16t^2-6t+110 h = 0 at the ground. divide both sides of the equation by (-2) to yield: 0 = 8t^2+3t - 55 and use quadratic equation h=<span>-b±√(b2 - 4ac)</span> 2awhere a = 8, b= 3, c=-55 Substitute: [-3 ± √(9 - 4*8*(-55))] / (16) = [6 ± √(36 + 1760)] / (16) = [6 ± √(1796)] /16 = (6 ± 42.3792)/16. Time can only be positive for this problem...so discard negative answer. = 48.3792/16 = 3.02 seconds
Answer:
w=1 5/24
Step-by-step explanation:
7/9-4/3w=-5/6
-4/3w=-5/6-7/9
-4/3w=-15/18-14/18
-4/3w=-29/18
w=-29/18:(-4/3)
w=29/18*(3/4)
w=29*3/18*4
w=29/6*4
w=29/24
w=1 5/24
The problem with this conclusion is that there is missing data.
In order for there to be a conclusion you must test it multiple times in order to see how certain the conclusion is.
Good Luck! :)
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Answer:
x≤9/2
Step-by-step explanation:
8x+15≤51
Subtract 15
8x+15-15≤51-15
8x+≤36
Divide by 8
8x/8≤36/8
x≤9/2
Answer:
The height of the hovercraft at the time of takeoff is 33 meters.
Step-by-step explanation:
Height of hovercraft x seconds after takeoff = h(x) = -(x - 11)(x + 3)
Height after takeoff is = h(0) = -(0 - 11)(0 + 3) = -(-11)(3) = 33
So the correct answer is 33 meters. The height of the hover craft at the time of the takeoff is 33 metres.
Answer: 33 meters.
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<em><u>Please mark brainliest</u></em>
<em><u>Hope this helps</u></em>
