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pychu [463]
3 years ago
11

PLEASE HELP!!!! 69 points my guy!!!

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0

Answer:

  • D. f(q) = 2q + 3

Step-by-step explanation:

<u>Given equation:</u>

  • 6q = 3s - 9

<u>q is independent variable, we need to solve it for s:</u>

  • 6q = 3s - 9
  • 3s = 6q + 9
  • s = 2q + 3

<u>Correct choice is </u>

  • D. f(q) = 2q + 3
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Helpp!! Please I appreciate it ​
11111nata11111 [884]

Answer:

x < -10

Step-by-step explanation:

Solve the inequality.

-2x + 4 > 24     Subtract 4 from both sides

-2x > 20           Divide both sides by -2

x < -10              We must flip the inequality sign because we divided by a negative number in the last step.

When you graph, draw a number line. Then, draw a circle on top of -10. Since x is less than -10, the arrow goes to the left of -10. Additionally, the circle on top of -10 will be an open circle because the inequality sign is a less than, not a less than or equal to.

I hope this helps and please mark me as brainliest!

3 0
3 years ago
A set of six single-digit integers has a unique mode of 2. What is the largest possible
Sliva [168]

Answer:

6.5

Step-by-step explanation:

We can assume that 2 is the smallest integer in the set. That means we would have a minimum of 2 2s. Then the largest integer in the set is 9. Since we can't have more than one 9 (due to the mode of 2), the next largest number we can have is 8. After that would be 7. Then the last digit would be 6. So now the set contains { 2, 2, 6, 7, 8, 9}. To find the median in an even set, we need to take the middle numbers and find the average. In this case, the two numbers are 6 and 7. The average of 6 and 7 is 6.5.

6 0
4 years ago
Read 2 more answers
Select all the true statements.
fiasKO [112]

Answer:

C and D are are the true statements

3 0
3 years ago
Not shure how to do this someone help!!
Anika [276]

-- the greatest common factor of the 15, the 9, and the 24 is 3 .

-- the greatest common factor of the b⁴, the b⁵, and the b³ is b³.

-- the greatest common factor of the c³, the c², and the c¹, is c¹.

-- the greatest common factor of the d², the d¹, and the d³ is d¹.

-- SO, the greatest common factor of the whole thing is  ( 3 b³ c d ) .

Can you factor that out of the big mess ?

Please try it.

You should get (3 b³cd) (5 bc²d - 3 b²c - 8 d²) .

7 0
3 years ago
The graph of f(x) is given on the right.
aleksklad [387]

Answer:

-1,3

Step-by-step explanation:

7 0
3 years ago
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