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2 years ago

A phone company charges for service according to the formula: C(n) = 13 +0.07%, where n is the number of minutes

Mathematics

1 answer:

irina1246 [14]2 years ago

6 0

Answer:

0.07

dollar per minute

Step-by-step explanation:

Given the charging formula :

C(n) = 13 +0.07n

n = number of minutes talked, and

C(n) = monthly charge, in dollars

The slope is the change in amount charged per change in the number of minutes talked.

Also, from The slope intercept equation :

y = mx + c

Comparing the equation :

0.07n = mx

m = 0.07

Since, The slope is the change in amount charged per change in the number of minutes talked.

Amount charged in dollars, talk time measured in minutes ;

Unit = dollar per minute

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Quadrilateral A has side lengths 6, 9, 9, and 12. Quadrilateral B is a scaled copy of Quadrilateral A, with its shortest side of

Alekssandra [29.7K]

Answer:

Look below

Step-by-step explanation:

Ok, you got a Quadrilateral with the side lengths 6, 9, 9, 12

The shortest of B is 2

Find the scale factor of the A to B

6 -> 2

6/2 = 3

Scale factor is 3

Now divide all the sides by scale factor

6/3, 9/3, 9/3, 12/3 = 2, 3, 3, 4

Add them all together to get the perimeter

2+3+3+4 = 12

Perimeter of B is 12

5 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$