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Genrish500 [490]
4 years ago
6

A student increases the temperature of a 417 cm3 balloon from 65°C to 126°C. What will the new volume of the balloon be?

Chemistry
1 answer:
Vinil7 [7]4 years ago
7 0

Answer:

492.3 cm³.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT. </em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If P and n are constant, and have different values of T and V:

<em>(V₁T₂) = (V₂T₁).</em>

V₁ = 417.0 cm³, T₁ = 65°C + 273 = 338 K.

V₂ = ??? cm³, T₂ = 126°C + 273 = 399 K.

<em>∴ V₂ = (V₁T₂)/(T₁) =</em> (417.0 cm³)(399 K)/(338 K) = <em>492.3 cm³.</em>

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