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kumpel [21]
3 years ago
6

2.

Mathematics
1 answer:
exis [7]3 years ago
5 0

Answer:

36-k

Step-by-step explanation:

You might be interested in
The sum of 3 times a number and 4 is no more than 10 and no less than -8.
larisa86 [58]

Answer:

Equation  -8 ≤ 3n+4 ≤ 10

Solution -4 ≤ n ≤ 2

Step-by-step explanation:

sum of 3 times a number and 4

3n+4

is no more than 10  

3n+4 ≤ 10

and no less than -8

-8 ≤ 3n+4 ≤ 10

To solve

Subtract 4 from all sides

-8-4 ≤ 3n+4-4 ≤ 10-4

-12 ≤ 3n ≤ 6

Divide all sides by 3

-12/3 ≤ 3n/3 ≤ 6/3

-4 ≤ n ≤ 2

3 0
3 years ago
The cost of 9 scarves is $83.25. What is the unit price?
melisa1 [442]

Answer:

9.25

Step-by-step explanation:

It's pretty simple all you have to do is 83.25 divided by 9.

7 0
3 years ago
State which of the following sets of ordered pairs represent a function.
zalisa [80]

Answer:

Option (D) is correct.

Step-by-step explanation:

A function can be termed as a process from a set of x values to a set of possible y-values where each x-value relates to exactly one y-value.

In other words, a relation can only be a function there is no repetition of x-values. It means a relation can not have duplicated inputs.

Given the sets

Set A: (5,2), (4, 3), (3, 4), (2,5)

Set B: (-1,-6), (0, 2), (1, 2), (3, 6)

Set C: (2, 1), (4, 2), (2, 3), (8,4)

It is clear that sets A and B represent the function because, in these sets, each x-value relates to exactly one y-value. In other words, there are no duplicated inputs.

But, set C has duplicated inputs i.e. x = 2 is repeated twice, and a function can not have a repeated input.

Therefore, we conclude that set A and set B represent a function.

Thus, option (D) is correct.

7 0
3 years ago
Which is the answer?
Tom [10]

Answer:

y=3x

Step-by-step explanation:

y=3x is the one according to values in the table

8 0
3 years ago
F(x)=√(10-3x) find the formula
Otrada [13]
Let y=f(x)
y=sqrt(10-3x)
you want to make x the subject

square both sides
y²=10-3x
3x=10-y²
x=(10-y²)/3

now replace y with x
f^-1(x)=(10-x²)/3
8 0
4 years ago
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