Question

4x+8≥5(3-x) solve with steps pleaseee!

Answer 1

Answer:

$x >\ or\ =\ \frac{7}{9}$

Step-by-step explanation:

$We\ are\ given\ that,\\4x+8>\ or =\ 5(3-x)\\Hence,\\We\ can\ treat\ inequality\ in\ the\ same\ way\ we\ do\ for\ solving\ equalities.\\Hence,\\4x+8>\ or\ =\ 5(3-x)\\By\ simplifying\ the\ RHS,\\4x+8 >\ or\ =\ 15-5x\\Hence,\\Adding\ (+5x)\ to\ the\ LHS\ and\ RHS,\\4x+8+(5x) >\ or\ =\ 15-5x+(5x)\\Simplifying,\\5x+4x+8 >\ or\ =\ 15+(5x-5x)\\9x+8 >\ or\ =\ 15\\Adding\ (-8)\ to\ both\ LHS\ and\ RHS,\\9x+8+(-8) >\ or\ =\ 15+(-8)\\Simplifying,\\9x+(8-8) >\ or\ =\ 7$

$9x >\ or\ =7\\x >\ or\ =\ \frac{7}{9}$

Answer 2

Step-by-step explanation:

4x+8≥5(3-x)

4x+8≥15-5x

adding 5x on each term

4x+5x+8≥15-5x+5x

9x+8≥15

subtract each term by 8

9x+8-8≥15-8

9x≥7

dividing each term by 9

9x/9=7/9

x≥7/9

is your answer