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zloy xaker [14]

3 years ago

15

threw 42 strikes out of 60 pitches in the first four innings of game two at the 1981 World Series. At this rate, if he threw 200

pitches during the entire series, how many strikes should he throw?

1 answer:

Fantom [35]3 years ago

7 0

Answer: 140 Strikes

Step-by-step explanation:

42 / 60 = .7 thats 70% Percent

The .7 x 200 = 140

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Answer:

480

Step-by-step explanation:

(16x10x8) divided by 2 = 480

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Nine less than three times a number is greater than forty

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Start with an equation.
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Step-by-step explanation:

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3 years ago

On a multiple choice test, if you randomly guessed on three questions, then what is the probability you got at least one of them

snow_lady [41]

Answer:

Number of Questions =3

Probability of giving a correct answer

$=\frac{1}{3}$

Probability of giving two correct answers

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Probability of giving all correct answers

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Probability that at least one of them is correct

$=_{1}^{3}\textrm{C}\\\\=\frac{3!}{(3-1)! \times1!}\\\\=3 \text{ways}\\\\=\frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \\\\=\frac{1}{27}$

Probability that two of them is correct

$=_{2}^{3}\textrm{C}\\\\=\frac{3!}{(3-2)! \times2!}\\\\=3 \text{ways}\\\\=\frac{2}{3} \times \frac{2}{3} \times \frac{2}{3} \\\\=\frac{8}{27}$

Probability that all of them is correct

$=_{3}^{3}\textrm{C}\\\\=\frac{3!}{(3-3)! \times3!}\\\\=1 \text{way}\\\\=1$

So, Required probability

$=\frac{1}{27} \times \frac{8}{27} \times 1\\\\=\frac{8}{729}$

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3 years ago